Identify the horizontal asymptote of h ( x ) = 1 2 ( 1 5 − x ) h ( x ) = \frac { 1 } { 2 } \left( 15 ^ { - x } \right) h ( x ) = 2 1 ( 1 5 − x ) .A) y = 1 2 y = \frac { 1 } { 2 } y = 2 1 B) y = 1 30 y = \frac { 1 } { 30 } y = 30 1 C) y = 1 15 y = \frac { 1 } { 15 } y = 15 1 D) y=15E) x -axis

Question

Identify the horizontal asymptote of   h ( x )  = 1 2 ( 1 5 − x )  h ( x )  = \frac { 1 } { 2 } \left( 15 ^ { - x } \right)  h ( x )  = 2 1 ​ ( 1 5 − x )    .A)    y = 1 2 y = \frac { 1 } { 2 } y = 2 1 ​ B)    y = 1 30 y = \frac { 1 } { 30 } y = 30 1 ​ C)    y = 1 15 y = \frac { 1 } { 15 } y = 15 1 ​ D)  y=15E) x -axis

Corwyn Asbury · Accepted Answer

Final Answer : E, Explanation :   The horizontal asymptote of   h ( x ) = 1 2 ( 1 5 − x ) h(x) = \frac{1}{2}(15^{-x}) h ( x ) = 2 1 ​ ( 1 5 − x )   is the x-axis, or   y = 0 y = 0 y = 0  , because as   x x x   approaches infinity,   1 5 − x 15^{-x} 1 5 − x   approaches 0, making the whole expression approach 0.

Identify the horizontal asymptote of $\frac { 1 } { 2 } \left( 15 ^ { - x } \right)$ .

A) $\frac { 1 } { 2 }$
B) $\frac { 1 } { 30 }$
C) $\frac { 1 } { 15 }$
D) y=15
E) x -axis

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Identify the horizontal asymptote of h(x) =12(15−x) h ( x ) = \frac { 1 } { 2 } \left( 15 ^ { - x } \right) h(x) =21​(15−x) .A) y=12y = \frac { 1 } { 2 }y=21​ B) y=130y = \frac { 1 } { 30 }y=301​ C) y=115y = \frac { 1 } { 15 }y=151​ D) y=15E) x -axis

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Learning Objectives

Learning Objectives

Related questions

Identify the horizontal asymptote of $\frac { 1 } { 2 } \left( 15 ^ { - x } \right)$ .

A) $\frac { 1 } { 2 }$
B) $\frac { 1 } { 30 }$
C) $\frac { 1 } { 15 }$
D) y=15
E) x -axis