Asked by Hesam Esmailian on May 15, 2024
Verified
Simplify the radical expression. −243x2y105\sqrt [ 5 ] { \frac { - 243 x ^ { 2 } } { y ^ { 10 } } }5y10−243x2
A) −6x25y8\frac { - 6 \sqrt [ 5 ] { x ^ { 2 } } } { y ^ { 8 } }y8−65x2
B) −6x25y5\frac { - 6 \sqrt [ 5 ] { x ^ { 2 } } } { y ^ { 5 } }y5−65x2
C) 9x25y8\frac { 9 \sqrt [ 5 ] { x ^ { 2 } } } { y ^ { 8 } }y895x2
D) −3x25y2\frac { - 3 \sqrt [ 5 ] { x ^ { 2 } } } { y ^ { 2 } }y2−35x2
E) −3x25y2\frac { - 3 \sqrt [ 5 ] { x ^ { 2 } } } { y ^ { 2 } }y2−35x2
Radical Expression
A term that features a symbol representing a square root, cube root, or any root of higher degree.
Negative Exponent
A power notation indicating division by the base raised to the absolute value of the exponent.
- Undertake the task of simplifying radical expressions, including those with square roots and roots exceeding the second degree.
- Manage operations related to radical expressions, incorporating addition, subtraction, and the process of making rational.
Verified Answer
KS
Kellie ShaughnessMay 21, 2024
Final Answer :
D
Explanation :
First, we can simplify the expression under the fifth root:
−243x2y10=−35x2y10=−(3x)2y10\frac{-243x^2}{y^{10}}=-\frac{3^5x^2}{y^{10}}=-\frac{(3x)^2}{y^{10}}y10−243x2=−y1035x2=−y10(3x)2
Now, we can take the fifth root:
−(3x)2y105=−(3x)25y105=−3xy21y85=−3x15y2y85=−3xy21y35=−3xy2y35\sqrt[5]{-\frac{(3x)^2}{y^{10}}}=-\frac{\sqrt[5]{(3x)^2}}{\sqrt[5]{y^{10}}}=-\frac{3x}{y^2}\sqrt[5]{\frac{1}{y^8}}=-\frac{3x\sqrt[5]{1}}{y^2\sqrt[5]{y^8}}=-\frac{3x}{y^2}\sqrt[5]{\frac{1}{y^3}}=-\frac{3x}{y^2\sqrt[5]{y^3}}5−y10(3x)2=−5y105(3x)2=−y23x5y81=−y25y83x51=−y23x5y31=−y25y33x
This is equivalent to choice D.
−243x2y10=−35x2y10=−(3x)2y10\frac{-243x^2}{y^{10}}=-\frac{3^5x^2}{y^{10}}=-\frac{(3x)^2}{y^{10}}y10−243x2=−y1035x2=−y10(3x)2
Now, we can take the fifth root:
−(3x)2y105=−(3x)25y105=−3xy21y85=−3x15y2y85=−3xy21y35=−3xy2y35\sqrt[5]{-\frac{(3x)^2}{y^{10}}}=-\frac{\sqrt[5]{(3x)^2}}{\sqrt[5]{y^{10}}}=-\frac{3x}{y^2}\sqrt[5]{\frac{1}{y^8}}=-\frac{3x\sqrt[5]{1}}{y^2\sqrt[5]{y^8}}=-\frac{3x}{y^2}\sqrt[5]{\frac{1}{y^3}}=-\frac{3x}{y^2\sqrt[5]{y^3}}5−y10(3x)2=−5y105(3x)2=−y23x5y81=−y25y83x51=−y23x5y31=−y25y33x
This is equivalent to choice D.
Learning Objectives
- Undertake the task of simplifying radical expressions, including those with square roots and roots exceeding the second degree.
- Manage operations related to radical expressions, incorporating addition, subtraction, and the process of making rational.
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