Asked by Courtney Mendez on May 15, 2024

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In an electronics company that produces transistors,1000 transistors are inspected at regular intervals.The proportion of nonconforming transistors produced by the process,estimated from data collected in a 1-month period,is In an electronics company that produces transistors,1000 transistors are inspected at regular intervals.The proportion of nonconforming transistors produced by the process,estimated from data collected in a 1-month period,is   = 0.0026.What would be the value of the lower control limit for a p chart of future samples of size 10,000? A) 0 B) 0.0011 C) 0.0021 D) This cannot be determined because the data involve samples of size 1000. = 0.0026.What would be the value of the lower control limit for a p chart of future samples of size 10,000?

A) 0
B) 0.0011
C) 0.0021
D) This cannot be determined because the data involve samples of size 1000.

Nonconforming Transistors

Transistors that do not meet specified criteria or operational standards set by quality control, often due to manufacturing defects.

Electronics Company

A company that designs, manufactures, and sells electronic equipment, devices, and consumer products.

Lower Control Limit

The lowest boundary in control charts that indicates the threshold below which a process may be out of control.

  • Comprehend the principle and utilization of p charts in observing characteristics of a process.
  • Implement understanding regarding the significance of sample sizes and their effect on the dependability of process capability indexes and control charts.
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CP
Coraima PerezMay 22, 2024
Final Answer :
B
Explanation :
The formula for the lower control limit for a p chart is given by LCL=p^−3p^(1−p^)nLCL=\hat{p}-3\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}LCL=p^3np^(1p^) where $\hat{p}$ is the estimated proportion of nonconforming items in the current process, and $n$ is the sample size. Here, $\hat{p}=0.0026$ and $n=10,000$, so LCL=0.0026−30.0026(1−0.0026)10000≈0.0011LCL=0.0026-3\sqrt{\frac{0.0026(1-0.0026)}{10000}}\approx0.0011LCL=0.00263100000.0026(10.0026)0.0011 Therefore, the answer is B.