Solve accurate to the cent: x 1 + 0.115 × 78 365 + 3 x ( 1 + 0.115 × 121 365 ) = $ 1000 ( 1 + 0.115 × 43 365 ) \frac{x}{1+0.115 imes \frac{78}{365}}+3 x\left(1+0.115 imes \frac{121}{365} ight)=\$ 1000\left(1+0.115 imes \frac{43}{365} ight) 1 + 0.115 × 365 78 x + 3 x ( 1 + 0.115 × 365 121 ) = $1000 ( 1 + 0.115 × 365 43 )

Question

Solve accurate to the cent: x 1 + 0.115 × 78 365 + 3 x ( 1 + 0.115 × 121 365 ) = $ 1000 ( 1 + 0.115 × 43 365 ) \frac{x}{1+0.115 	imes \frac{78}{365}}+3 x\left(1+0.115 	imes \frac{121}{365}ight)=\$ 1000\left(1+0.115 	imes \frac{43}{365}ight) 1 + 0.115 × 365 78 ​ x ​ + 3 x ( 1 + 0.115 × 365 121 ​ ) = $1000 ( 1 + 0.115 × 365 43 ​ )

kawal singh · Accepted Answer

Final Answer :  x = $247.79

Solve accurate to the cent:
$x1+0.115×78365+3x(1+0.115×121365)=$1000(1+0.115×43365)\frac{x}{1+0.115 \times \frac{78}{365}}+3 x\left(1+0.115 \times \frac{121}{365}\right)=\$ 1000\left(1+0.115 \times \frac{43}{365}\right)$

Definitions

Learning Objectives

Learning Objectives

Related questions

Solve accurate to the cent: x1+0.115×78365+3x(1+0.115×121365)=$1000(1+0.115×43365)\frac{x}{1+0.115 \times \frac{78}{365}}+3 x\left(1+0.115 \times \frac{121}{365}\right)=\$ 1000\left(1+0.115 \times \frac{43}{365}\right)1+0.115×36578​x​+3x(1+0.115×365121​)=$1000(1+0.115×36543​)

Definitions

Learning Objectives

Learning Objectives

Related questions

Solve accurate to the cent:
$x1+0.115×78365+3x(1+0.115×121365)=$1000(1+0.115×43365)\frac{x}{1+0.115 \times \frac{78}{365}}+3 x\left(1+0.115 \times \frac{121}{365}\right)=\$ 1000\left(1+0.115 \times \frac{43}{365}\right)$