Find the solution (if any) to the equation. $3x4+x+74=0\sqrt [ 4 ] { 3 x } + \sqrt [ 4 ] { x + 7 } = 0$

A) x= $\frac { 7 } { 4 }$
B) x=-4
C) $x =$ $72\frac { 7 } { 2 }$
D) $x = 0$
E) no solution

Question

Find the solution (if any) to the equation.

3x4+x+74=0\sqrt [ 4 ] { 3 x } + \sqrt [ 4 ] { x + 7 } = 0

A) x=

\frac { 7 } { 4 }

B) x=-4
C)

x =

72\frac { 7 } { 2 }

D)

x = 0

E) no solution

Kumul Hooks · Accepted Answer

Final Answer : E, Explanation :  We cannot take the fourth root of a negative number (since an even root of a negative number is imaginary). Therefore, there is no real solution to this equation.

Find the solution (if any) to the equation. $3x4+x+74=0\sqrt [ 4 ] { 3 x } + \sqrt [ 4 ] { x + 7 } = 0$

A) x= $\frac { 7 } { 4 }$
B) x=-4
C) $x =$ $72\frac { 7 } { 2 }$
D) $x = 0$
E) no solution

Definitions

Learning Objectives

Learning Objectives

Related questions

Find the solution (if any) to the equation. 3x4+x+74=0\sqrt [ 4 ] { 3 x } + \sqrt [ 4 ] { x + 7 } = 043x​+4x+7​=0 A) x= −74- \frac { 7 } { 4 }−47​ B) x=-4C) x=x =x= 72\frac { 7 } { 2 }27​ D) x=0x = 0x=0 E) no solution

Definitions

Learning Objectives

Learning Objectives

Related questions

Find the solution (if any) to the equation. $3x4+x+74=0\sqrt [ 4 ] { 3 x } + \sqrt [ 4 ] { x + 7 } = 0$

A) x= $\frac { 7 } { 4 }$
B) x=-4
C) $x =$ $72\frac { 7 } { 2 }$
D) $x = 0$
E) no solution