If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be:

A) 2.7969
B) 2.7874
C) 2.4922
D) 2.4851
E) 2.3562

Question

Jacob Walker · Accepted Answer

Final Answer : A, Explanation :  To find the critical value of t for a 99% confidence interval with n=25, we need to use the t-distribution with degrees of freedom (df) equal to n-1 = 24. We can find the critical value using a statistical software or a t-table. For a two-tailed test with alpha level of 0.01 (since we want to find a 99% confidence interval), the critical value of t with 24 degrees of freedom is 2.7969. Therefore, the correct answer is A.

If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be:

A) 2.7969
B) 2.7874
C) 2.4922
D) 2.4851
E) 2.3562

Definitions

Learning Objectives

Learning Objectives

Related questions

If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be:A) 2.7969B) 2.7874C) 2.4922D) 2.4851E) 2.3562

Definitions

Learning Objectives

Learning Objectives

Related questions

If you were constructing a 99% confidence interval of the population mean based on a sample of n = 25 where the standard deviation of the sample s = 0.05, the critical value of t will be:

A) 2.7969
B) 2.7874
C) 2.4922
D) 2.4851
E) 2.3562