Calculate the final result to two decimal places, where z = .1515 $z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}$

A) .48
B) 2.65
C) 1.48
D) 3.22
E) 5.48

Question

Calculate the final result to two decimal places, where z = .1515

z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}

A) .48
B) 2.65
C) 1.48
D) 3.22
E) 5.48

Zybrea Knight · Accepted Answer

Final Answer : C, Explanation :   First, calculate each term with z = .1515:-   z 4 = . 1515 4 = . 037875 \frac{z}{4} = \frac{.1515}{4} = .037875 4 z ​ = 4 .1515 ​ = .037875  -   z 4 = ( . 1515 ) 4 = . 000053034 z^{4} = (.1515)^{4} = .000053034 z 4 = ( .1515 ) 4 = .000053034  -   7 9 = . 777777... \frac{7}{9} = .777777... 9 7 ​ = .777777...  -   − . 25 z 2 = − . 25 ( . 1515 ) 2 = − . 25 ( . 02295225 ) = − . 005738 -.25z^{2} = -.25(.1515)^{2} = -.25(.02295225) = -.005738 − .25 z 2 = − .25 ( .1515 ) 2 = − .25 ( .02295225 ) = − .005738  -   2 3 = . 666666... \frac{2}{3} = .666666... 3 2 ​ = .666666...  Adding these together:.037875 + .000053034 + .777777 - .005738 + .666666 = 1.476633034Rounded to two decimal places, the final result is 1.48.

Calculate the final result to two decimal places, where z = .1515 $z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}$

A) .48
B) 2.65
C) 1.48
D) 3.22
E) 5.48

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Learning Objectives

Learning Objectives

Related questions

Calculate the final result to two decimal places, where z = .1515 z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}4z​+z4+97​−.25z2+32​ A) .48B) 2.65C) 1.48D) 3.22E) 5.48

Definitions

Learning Objectives

Learning Objectives

Related questions

Calculate the final result to two decimal places, where z = .1515 $z4+z4+79−.25z2+23\frac{z}{4}+z^{4}+\frac{7}{9}-.25 z^{2}+\frac{2}{3}$

A) .48
B) 2.65
C) 1.48
D) 3.22
E) 5.48