Asked by Shakeya Burkhalter on Sep 28, 2024
Verified
The two most abundant isotopes of boron are 10B and 11B, with 11B being about 4 times more abundant. In the mass spectrum of trimethylborate [(CH3O) 3B], ________.
A) the peaks at m/z 103 and m/z 104 have equivalent intensities
B) the peak at m/z 103 has an intensity which is 4 times that of the m/z 104 peak
C) the peak at m/z 103 has an intensity which is 1/4 the intensity of the peak at m/z 104
D) none of the above
Boron Isotopes
Variants of the element boron, differing in the number of neutrons in the nucleus and having distinct nuclear properties.
Trimethylborate
A chemical compound with the formula B(OCH3)3, used as a reagent in organic synthesis and as a flame retardant.
- Acquire knowledge on how the abundance of isotopes affects mass spectrometric peaks.
Verified Answer
LG
Losirma Ganda1 day ago
Final Answer :
C
Explanation :
The most abundant isotopes of boron are ^10B and ^11B, with ^11B being about 4 times more abundant than ^10B. In the mass spectrum of trimethylborate, which contains boron, the peak corresponding to the molecule containing ^11B (m/z 104) would be 4 times more intense than the peak for the molecule containing ^10B (m/z 103), reflecting the natural abundance ratio of these boron isotopes.
Learning Objectives
- Acquire knowledge on how the abundance of isotopes affects mass spectrometric peaks.