Compete the table and use the results to sketch the graph of the equation $y=|x-1|$ .
$\begin{array}{llllll}x& -2& -1& 0& 1& 2\\ y& & & & & \end{array}$

A)
B)
C)
D)
E)

To complete the table, we need to substitute each given value of x, one at a time, into the equation $y = | x - 1 |$, and evaluate.
For $x=-2$, $y = | -2 - 1 | = 3$
For $x=-1$, $y = | -1 - 1 | = 2$
For $x=0$, $y = | 0 - 1 | = 1$
For $x=1$, $y = | 1 - 1 | = 0$
For $x=2$, $y = | 2 - 1 | = 1$
Now we can plot these points on the coordinate plane and sketch the graph of $y = | x - 1 |$. The graph is symmetric about the vertical line $x = 1$, and consists of two segments: one with a slope of 1, passing through (1, 0), and another with a slope of -1, passing through (0, 1). The graph looks like a "\V/" shape with its vertex at (1,0), as shown in choice D.