Asked by Claire Liang on Jun 09, 2024
Verified
Consider the following partial ANOVA table: 
The numerator and denominator degrees of freedom (identified by asterisks) are:
A) 4 and 15
B) 3 and 16
C) 15 and 4
D) 16 and 3
E) 6 and 16
Degrees of Freedom
The number of independent values or quantities that can vary in the analysis of statistical data, which are necessary to calculate a statistic.
Partial ANOVA Table
A table that presents results from an Analysis of Variance test, but might not include all elements typically found in a full ANOVA table, such as missing data on certain variables or groups.
- Acquire knowledge on the notion of degrees of freedom and how it is calculated within the framework of ANOVA.
Verified Answer
MA
Mitchell AshbaughJun 16, 2024
Final Answer :
B
Explanation :
In the partial ANOVA table, the numerator degrees of freedom for the Treatment is 3 and for the Error is (16-3) = 13. The denominator degrees of freedom for the F-test of Treatment is (4-1) = 3 and for the F-test of Error is (16-4) = 12. Therefore, the answer is option B, with numerator degrees of freedom being 3 and denominator degrees of freedom being 16.
Learning Objectives
- Acquire knowledge on the notion of degrees of freedom and how it is calculated within the framework of ANOVA.
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