Asked by Pulse Survey on Sep 23, 2024

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Determine whether the sequence ln⁡7,ln⁡14,ln⁡21,ln⁡28,…\ln 7 , \ln 14 , \ln 21 , \ln 28 , \ldotsln7,ln14,ln21,ln28, is arithmetic. If so, find the common difference.

A) arithmetic; 14
B) arithmetic; 2
C) arithmetic;7
D) arithmetic; 28
E) not arithmetic

Arithmetic

A branch of mathematics dealing with numbers and basic operations such as addition, subtraction, multiplication, and division.

Common Difference

The constant difference between successive terms of an arithmetic sequence.

Sequence

A set of numbers arranged in a specific order, where each number is related to one or more numbers before/after it according to a specific rule.

  • Identify and classify sequences as arithmetic or geometric.
  • Calculate the common difference of arithmetic sequences.
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Nadeen Shafeeq2 days ago
Final Answer :
E
Explanation :
The sequence is not arithmetic because the difference between consecutive terms is not constant. In an arithmetic sequence, the difference between any two successive terms is the same. Here, the sequence is given by the natural logarithm of consecutive multiples of 7 ( ln⁡7,ln⁡14,ln⁡21,ln⁡28,…\ln 7, \ln 14, \ln 21, \ln 28, \ldotsln7,ln14,ln21,ln28, ). The difference between successive terms, for example, ln⁡14−ln⁡7=ln⁡(14/7)=ln⁡2\ln 14 - \ln 7 = \ln(14/7) = \ln 2ln14ln7=ln(14/7)=ln2 and ln⁡21−ln⁡14=ln⁡(21/14)=ln⁡(3/2)\ln 21 - \ln 14 = \ln(21/14) = \ln(3/2)ln21ln14=ln(21/14)=ln(3/2) , is not constant. Therefore, the sequence is not arithmetic.