Find a true inequality that involves the real number 11 6 \frac { 11 } { 6 } 6 11 .A) 11 6 \frac { 11 } { 8 } 6 11 8 11 C) \frac { 17 } { 6 } 11 6 17 6 \frac { 11 } { 6 } \frac { 17 } { 6 } 6 11 6 17 D) 11 6

Question

Find a true inequality that involves the real number

116\frac { 11 } { 6 }

.

A)

116<56\frac { 11 } { 6 } < \frac { 5 } { 6 }

B)

116>118\frac { 11 } { 6 } > \frac { 11 } { 8 }

C)

116>176\frac { 11 } { 6 } > \frac { 17 } { 6 }

D)

116<119\frac { 11 } { 6 } < \frac { 11 } { 9 }

E)

116<−176\frac { 11 } { 6 } < - \frac { 17 } { 6 }

Basheer Maflahi · Accepted Answer

Final Answer : B, Explanation :   11 6 \frac { 11 } { 6 } 6 11 ​   is greater than   11 8 \frac { 11 } { 8 } 8 11 ​   because when comparing fractions with the same numerator, the fraction with the smaller denominator is larger.

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