Asked by William McGinnis on Jun 10, 2024

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Find the constant of proportionality given s=kts = k ts=kt , and s=60s = 60s=60 when t=6t = 6t=6 .

A) 101010
B) 606060
C) 111111
D) 666
E) 777

Constant of Proportionality

The fixed value that relates two proportional quantities.

  • Calculate the constant of proportionality in direct and inverse proportionality equations.
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JH
Jaylyn HollandJun 12, 2024
Final Answer :
A
Explanation :
The constant of proportionality kkk can be found by rearranging the equation s=kts = kts=kt to k=stk = \frac{s}{t}k=ts . Substituting s=60s = 60s=60 and t=6t = 6t=6 gives k=606=10k = \frac{60}{6} = 10k=660=10 .