Asked by Daniela Lopez on May 07, 2024
Verified
Find the height in feet of a free-falling object at time t=5 using the function s=−16t2+76t+118s = - 16 t ^ { 2 } + 76 t + 118s=−16t2+76t+118 .
A) 138 feet
B) 98 feet
C) 20 feet
D) 662 feet
E) 898 feet
Free-Falling Object
An object that is under the influence of gravity only, with no other forces acting upon it.
- Use algebraic approaches to tackle real-world challenges associated with velocity and space.
Verified Answer
CJ
carissa juarezMay 09, 2024
Final Answer :
B
Explanation :
To find the height at time t=5, we need to substitute t=5 into the given function.
$s = - 16 t ^ { 2 } + 76 t + 118$
$s = - 16 (5)^2 + 76 (5) + 118$
$s = - 400 + 380 + 118$
$s = 98$
Therefore, the height of the free-falling object at time t=5 is 98 feet, which corresponds to choice B.
$s = - 16 t ^ { 2 } + 76 t + 118$
$s = - 16 (5)^2 + 76 (5) + 118$
$s = - 400 + 380 + 118$
$s = 98$
Therefore, the height of the free-falling object at time t=5 is 98 feet, which corresponds to choice B.
Learning Objectives
- Use algebraic approaches to tackle real-world challenges associated with velocity and space.