Find the intercepts of y = 9 x 2 − 8 x + 8 y = 9 x ^ { 2 } - 8 x + 8 y = 9 x 2 − 8 x + 8 .A) x -intercept: ( − 4 9 , 0 ) \left( - \frac { 4 } { 9 } , 0 \right) ( − 9 4 , 0 ) y -intercepts: (0,8)B) no x -intercepts y -intercept: (0,8)C) x -intercept: (8,0) no y -interceptsD) no x -intercepts y -intercept: (0,-8)E) x -intercept: (8,0) y -intercept: (0,8)

Question

Find the intercepts of    y = 9 x 2 − 8 x + 8 y = 9 x ^ { 2 } - 8 x + 8 y = 9 x 2 − 8 x + 8   .A) x -intercept:   ( − 4 9 , 0 )  \left( - \frac { 4 } { 9 } , 0 \right)  ( − 9 4 ​ , 0 )    y -intercepts: (0,8)B) no x -intercepts y -intercept: (0,8)C) x -intercept: (8,0)  no y -interceptsD) no x -intercepts y -intercept: (0,-8)E) x -intercept: (8,0)  y -intercept: (0,8)

omolayo popoola · Accepted Answer

Final Answer : B, Explanation :   To find the y-intercept, set   x = 0 x = 0 x = 0  , which gives   y = 8 y = 8 y = 8  , so the y-intercept is (0,8). For the x-intercepts, solve   9 x 2 − 8 x + 8 = 0 9x^2 - 8x + 8 = 0 9 x 2 − 8 x + 8 = 0  . The discriminant of this quadratic equation is   b 2 − 4 a c = ( − 8 ) 2 − 4 ( 9 ) ( 8 ) = 64 − 288 = − 224 b^2 - 4ac = (-8)^2 - 4(9)(8) = 64 - 288 = -224 b 2 − 4 a c = ( − 8 ) 2 − 4 ( 9 ) ( 8 ) = 64 − 288 = − 224  , which is negative, indicating there are no real x-intercepts.

Find the intercepts of $y = 9 x ^ { 2 } - 8 x + 8$ .

A) x -intercept: $\left( - \frac { 4 } { 9 } , 0 \right)$ y -intercepts: (0,8)
B) no x -intercepts y -intercept: (0,8)
C) x -intercept: (8,0) no y -intercepts
D) no x -intercepts y -intercept: (0,-8)
E) x -intercept: (8,0) y -intercept: (0,8)

Definitions

Learning Objectives

Learning Objectives

Related questions