For a particular gene, the frequency of the dominant allele H is 0.65. The total population size is 10,000 individuals. In addition, the homozygous recessive condition results in living but sterile offspring. Fill in the table of values for the generations indicated:
Does this population exhibit Hardy-Weinberg equilibrium? Why or why not? If not, what assumptions does the Hardy-Weinberg principle make that appear to be inapplicable in this situation?

Concepts to Consider: The Hardy-Weinberg equation allows students to calculate the value for q (0.35) based on the frequency of H (= p ). The values for the particular genotypes are then processed mathematically (the last three columns of the table for generation 1 are 4,225 individuals; 4,550 individuals; 1,225 individuals). The values of p and q in the second generation are based on the fact that the individuals with the recessive genotype ( q ²) are sterile and are therefore removed from the reproductive population. The number of alleles in the population equals the number of surviving offspring × 2, or 17,610. Of these, 13,060 are dominant H alleles (the number of homozygous dominant individuals × 2 + the number of heterozygous individuals) and 4,550 are recessive h alleles. This allows for the calculation of new values for p (0.74) and q (0.26) with associated changes in the number of individuals with each genotype.