Given N = 600, M = 40, SD = 10 (Normal Distribution) , approximately how many individuals would you expect to score between 20 and 30?

A) 12
B) 204
C) 300
D) 84

To find the number of individuals scoring between 20 and 30, we first calculate the z-scores for 20 and 30. Z = (X - M) / SD, where X is the score, M is the mean, and SD is the standard deviation. For 20: Z = (20 - 40) / 10 = -2. For 30: Z = (30 - 40) / 10 = -1. Looking at a standard normal distribution table, the area between Z = -2 and Z = -1 is approximately 0.1359 (or 13.59%). Therefore, the number of individuals is 0.1359 * 600 ≈ 81.54, which rounds to approximately 84 individuals.