Given the following data, find the expected breakdown cost. The cost per breakdown is $200.
$51210185\begin{array} { | l | c | c | c | c | c | } \hline \text { Number of breakdowns per week } & 0 & 1 & 2 & 3 & 4 \\\hline \text { Weekly frequency } & 5 & 12 & 10 & 18 & 5 \\\hline\end{array}$

Question

Given the following data, find the expected breakdown cost. The cost per breakdown is $200.  Number of breakdowns per week  0 1 2 3 4  Weekly frequency  5 12 10 18 5 \begin{array} { | l | c | c | c | c | c | } \hline 	ext { Number of breakdowns per week }  &  0  &  1  &  2  &  3  &  4 \\hline 	ext { Weekly frequency }  &  5  &  12  &  10  &  18  &  5 \\hline\end{array}  Number of breakdowns per week   Weekly frequency  ​ 0 5 ​ 1 12 ​ 2 10 ​ 3 18 ​ 4 5 ​ ​

Diana Henry · Accepted Answer

Final Answer :   Number of breakdowns per week  0 1 2 3 4  Total   Weekly Probability  . 10 . 24 . 20 . 36 . 10 1.00 \begin{array} { | l | c | c | c | c | c | c | } \hline 	ext { Number of breakdowns per week }  &  0  &  1  &  2  &  3  &  4  &  	ext { Total } \\hline 	ext { Weekly Probability }  &  .10  &  .24  &  .20  &  .36  &  .10  &  1.00 \\hline\end{array}  Number of breakdowns per week   Weekly Probability  ​ 0 .10 ​ 1 .24 ​ 2 .20 ​ 3 .36 ​ 4 .10 ​  Total  1.00 ​ ​   Expected number of breakdowns = (0 ∗ .10) + (1 ∗ .24) + (2 ∗ .20) + (3 ∗ .36) + (4 ∗ .10) = 2.12Expected cost of breakdowns = 2.12 ∗ $200 = $424.

Given the following data, find the expected breakdown cost. The cost per breakdown is $200.
$51210185\begin{array} { | l | c | c | c | c | c | } \hline \text { Number of breakdowns per week } & 0 & 1 & 2 & 3 & 4 \\\hline \text { Weekly frequency } & 5 & 12 & 10 & 18 & 5 \\\hline\end{array}$

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