Asked by Giselle Saldana on May 09, 2024

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In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 64 business students over a one-week period.Assume the population standard deviation is 1.6 hours.With a .95 probability, the margin of error is approximately

A) .392.
B) 1.96.
C) .20.
D) 1.645.

Population standard deviation

A measure of the dispersion of a set of data from its mean, calculated for the entire population.

Confidence interval

A range of values, derived from the sample statistics, that is likely to contain the value of an unknown population parameter.

  • Engage accurate computational methods for the standard error of the mean and the margin of error in numerous situations.
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Savannah TaylorMay 12, 2024
Final Answer :
A
Explanation :
The margin of error (ME) can be calculated using the formula ME = Z * (σ/√n), where Z is the Z-score corresponding to the confidence level (1.96 for 95%), σ is the population standard deviation (1.6 hours), and n is the sample size (64). Plugging in the values gives ME = 1.96 * (1.6/√64) = 1.96 * 0.2 = 0.392.