Asked by Emily Faith on May 20, 2024
Verified
Multiply (3+8i) (2−13i) ( 3 + 8 i ) ( 2 - 13 i ) (3+8i) (2−13i) and write in standard form.
A) −110+23i- 110 + 23 i−110+23i
B) 23+110i23 + 110 i23+110i
C) −110−23i- 110 - 23 i−110−23i
D) 110−23i110 - 23 i110−23i
E) −23−23i- 23 - 23 i−23−23i
Multiply
The operation of repeated addition of the same number.
- Perform operations with complex numbers in standard form.
Verified Answer
SS
Simeon SkoufezisMay 25, 2024
Final Answer :
D
Explanation :
Apply the distributive property and use the fact that $i^2=-1$.
(3+8i)(2−13i)=3(2)−3(13i)+8i(2)−8i(13i)=6−39i+16i+104=110−23i\begin{align*}( 3 + 8 i ) ( 2 - 13 i ) &= 3(2) - 3(13i) + 8i(2) - 8i(13i)\\&= 6 - 39i + 16i + 104\\&=110 - 23i\end{align*}(3+8i)(2−13i)=3(2)−3(13i)+8i(2)−8i(13i)=6−39i+16i+104=110−23i
Therefore, the answer is choice D.
(3+8i)(2−13i)=3(2)−3(13i)+8i(2)−8i(13i)=6−39i+16i+104=110−23i\begin{align*}( 3 + 8 i ) ( 2 - 13 i ) &= 3(2) - 3(13i) + 8i(2) - 8i(13i)\\&= 6 - 39i + 16i + 104\\&=110 - 23i\end{align*}(3+8i)(2−13i)=3(2)−3(13i)+8i(2)−8i(13i)=6−39i+16i+104=110−23i
Therefore, the answer is choice D.
Learning Objectives
- Perform operations with complex numbers in standard form.