Asked by Emily Faith on May 20, 2024

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Multiply (3+8i) (2−13i) ( 3 + 8 i ) ( 2 - 13 i ) (3+8i) (213i) and write in standard form.

A) −110+23i- 110 + 23 i110+23i
B) 23+110i23 + 110 i23+110i
C) −110−23i- 110 - 23 i11023i
D) 110−23i110 - 23 i11023i
E) −23−23i- 23 - 23 i2323i

Multiply

The operation of repeated addition of the same number.

  • Perform operations with complex numbers in standard form.
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Verified Answer

SS
Simeon SkoufezisMay 25, 2024
Final Answer :
D
Explanation :
Apply the distributive property and use the fact that $i^2=-1$.
(3+8i)(2−13i)=3(2)−3(13i)+8i(2)−8i(13i)=6−39i+16i+104=110−23i\begin{align*}( 3 + 8 i ) ( 2 - 13 i ) &= 3(2) - 3(13i) + 8i(2) - 8i(13i)\\&= 6 - 39i + 16i + 104\\&=110 - 23i\end{align*}(3+8i)(213i)=3(2)3(13i)+8i(2)8i(13i)=639i+16i+104=11023i
Therefore, the answer is choice D.