Asked by Orion Lavigne on May 09, 2024

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Multiply and simplify. 12u6v7u+v⋅u+v18u5\frac { 12 u ^ { 6 } v } { 7 u + v } \cdot \frac { u + v } { 18 u ^ { 5 } }7u+v12u6v18u5u+v

A) 6uv7,u≠0\frac { 6 u v } { 7 } , u \neq 076uv,u=0
B) u+v7,u≠0\frac { u + v } { 7 } , u \neq 07u+v,u=0
C) 2uv(u+v) 3(7u+v) ,u≠0\frac { 2 u v ( u + v ) } { 3 ( 7 u + v ) } , u \neq 03(7u+v) 2uv(u+v) ,u=0
D) 2(u+v) 3(7u+v) ,u≠0\frac { 2 ( u + v ) } { 3 ( 7 u + v ) } , u \neq 03(7u+v) 2(u+v) ,u=0
E) 67u+v,u≠0\frac { 6 } { 7 u + v } , u \neq 07u+v6,u=0

Multiply

The mathematical operation of increasing one number by another number, essentially repeated addition.

Simplify

To alter a mathematical expression or equation to make it easier to understand or work with by reducing it to its most basic form.

  • Conduct multiplication and division activities with algebraic fractions.
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CS
Catlyn SimmonsMay 13, 2024
Final Answer :
C
Explanation :
We start by simplifying each fraction individually.

12u6v7u+v=4u5⋅3uv7u+v\frac { 12 u ^ { 6 } v } { 7 u + v } = \frac{4u^5 \cdot 3u v}{7u + v}7u+v12u6v=7u+v4u53uv
u+v18u5=118u4(u+v)\frac { u + v } { 18 u ^ { 5 } } = \frac{1}{18u^4}(u+v)18u5u+v=18u41(u+v)

Now, we can multiply the two fractions.

12u6v7u+v⋅u+v18u5=4u5⋅3uv7u+v⋅118u4(u+v)\frac { 12 u ^ { 6 } v } { 7 u + v } \cdot \frac { u + v } { 18 u ^ { 5 } } = \frac{4u^5 \cdot 3u v}{7u + v}\cdot \frac{1}{18u^4}(u+v)7u+v12u6v18u5u+v=7u+v4u53uv18u41(u+v)
=12u6v7u+v⋅118u4(u+v)=(C) 2uv(u+v)3(7u+v), for u≠0=\frac{12u^6v}{7u+v} \cdot \frac{1}{18u^4}(u+v) = \boxed{\textbf{(C) } \frac{2 u v ( u + v )}{3 ( 7 u + v )}}, \text{ for }u\neq0=7u+v12u6v18u41(u+v)=(C) 3(7u+v)2uv(u+v), for u=0