Asked by Alondra Luna-Muniz on May 29, 2024
Verified
Multiply and simplify. 27s825s⋅15s7243s\frac { 27 s ^ { 8 } } { 25 s } \cdot \frac { 15 s ^ { 7 } } { 243 s }25s27s8⋅243s15s7
A) s1315,s≠0\frac { s ^ { 13 } } { 15 } , s \neq 015s13,s=0
B) s143,s≠0\frac { s ^ { 14 } } { 3 } , s \neq 03s14,s=0
C) s1730,s≠0\frac { s ^ { 17 } } { 30 } , s \neq 030s17,s=0
D) s1610,s≠0\frac { s ^ { 16 } } { 10 } , s \neq 010s16,s=0
E) s135,s≠0\frac { s ^ { 13 } } { 5 } , s \neq 05s13,s=0
Multiply
The mathematical operation of increasing one number by another number.
- Carry out multiplication and division processes with expressions involving fractions.
Verified Answer
CM
classic margaritaJun 03, 2024
Final Answer :
A
Explanation :
When multiplying fractions, you multiply the numerators together and the denominators together. Simplifying the expression 27s825s⋅15s7243s\frac { 27 s ^ { 8 } } { 25 s } \cdot \frac { 15 s ^ { 7 } } { 243 s }25s27s8⋅243s15s7 , you get 27⋅15⋅s8⋅s725⋅243⋅s⋅s\frac { 27 \cdot 15 \cdot s^{8} \cdot s^{7} } { 25 \cdot 243 \cdot s \cdot s }25⋅243⋅s⋅s27⋅15⋅s8⋅s7 . Simplifying further, 27⋅15=40527 \cdot 15 = 40527⋅15=405 and 25⋅243=607525 \cdot 243 = 607525⋅243=6075 , which simplifies to 1⋅s1515\frac { 1 \cdot s^{15} } { 15 }151⋅s15 , or s1515\frac { s^{15} } { 15 }15s15 , considering s≠0s \neq 0s=0 to avoid division by zero. However, it seems there was a mistake in my calculation of the powers of sss and the simplification of the coefficients. Correctly simplifying the powers of sss gives s8+7−1−1=s13s^{8+7-1-1} = s^{13}s8+7−1−1=s13 , and correctly simplifying the coefficients gives 4056075=115\frac{405}{6075} = \frac{1}{15}6075405=151 , leading to the correct answer of s1315\frac{s^{13}}{15}15s13 , with the condition s≠0s \neq 0s=0 .
Learning Objectives
- Carry out multiplication and division processes with expressions involving fractions.