Of 346 items tested,12 are found to be defective.Construct a 98% confidence interval for the percentage of all such items that are defective.

A) (1.18%,5.76%)
B) (0.93%,6.00%)
C) (3.34%,3.59%)
D) (1.85%,5.09%)
E) (0.13%,6.80%)

The confidence interval for a proportion can be calculated using the formula: $$CI=\hat{p}\pm Z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$$ where $\hat{p}$ is the sample proportion (12/346), $n$ is the sample size (346), and $Z$ is the Z-score corresponding to the confidence level (for 98%, Z ≈ 2.33). Plugging in the values, we get the confidence interval as approximately (1.18%, 5.76%).