Asked by Brett Parker on Mar 10, 2024

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Perform the indicated operations and simplify. Assume that all exponents represent positive integers. (−2x3n+2x2n−4xn) −(5x2n+3xn−2) \left( - 2 x ^ { 3 n } + 2 x ^ { 2 n } - 4 x ^ { n } \right) - \left( 5 x ^ { 2 n } + 3 x ^ { n } - 2 \right) (2x3n+2x2n4xn) (5x2n+3xn2)

A) −2x3n−3x2n−7xn+2- 2 x ^ { 3 n } - 3 x ^ { 2 n } - 7 x ^ { n } + 22x3n3x2n7xn+2
B) −7x3n−3x2n−7xn+2- 7 x ^ { 3 n } - 3 x ^ { 2 n } - 7 x ^ { n } + 27x3n3x2n7xn+2
C) −7x3n−x2n−2xn−2- 7 x ^ { 3 n } - x ^ { 2 n } - 2 x ^ { n } - 27x3nx2n2xn2
D) −2x3n+7x2n−xn−2- 2 x ^ { 3 n } + 7 x ^ { 2 n } - x ^ { n } - 22x3n+7x2nxn2
E) −7x3n−x2n−2xn- 7 x ^ { 3 n } - x ^ { 2 n } - 2 x ^ { n }7x3nx2n2xn

Positive Integers

Natural numbers greater than zero (1, 2, 3, ...).

Exponents

Mathematical notation indicating the number of times a base number is multiplied by itself.

  • Perform operations and simplifications involving algebraic expressions.
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DK
Drx Khushboo VermaMar 10, 2024
Final Answer :
A
Explanation :
Subtracting the second polynomial from the first, we combine like terms: −2x3n+(2x2n−5x2n)+(−4xn−3xn)+2=−2x3n−3x2n−7xn+2-2x^{3n} + (2x^{2n} - 5x^{2n}) + (-4x^n - 3x^n) + 2 = -2x^{3n} - 3x^{2n} - 7x^n + 22x3n+(2x2n5x2n)+(4xn3xn)+2=2x3n3x2n7xn+2 .