Asked by Eytan Weisz on May 20, 2024
Verified
Solve 2y(y−16) +5(y−16) =02 y ( y - 16 ) + 5 ( y - 16 ) = 02y(y−16) +5(y−16) =0 .
A) y=16,y=−5y = 16 , y = - 5y=16,y=−5
B) y=−16,y=25y = - 16 , y = \frac { 2 } { 5 }y=−16,y=52
C) y=16,y=−52y = 16 , y = - \frac { 5 } { 2 }y=16,y=−25
D) y=16,y=−25y = 16 , y = - \frac { 2 } { 5 }y=16,y=−52
E) y=−16,y=−52y = - 16 , y = - \frac { 5 } { 2 }y=−16,y=−25
Quadratic Equation
A mathematical equation of the form ax^2 + bx + c = 0, where x represents an unknown variable, and a, b, and c are constants with a ≠ 0.
- Apply the quadratic formula to determine the solutions of quadratic equations.
Verified Answer
PS
Priyanka ShindeMay 26, 2024
Final Answer :
C
Explanation :
First, factor out the common term y−16y - 16y−16 , giving (y−16)(2y+5)=0 ( y - 16 ) ( 2 y + 5 ) = 0 (y−16)(2y+5)=0 . Setting each factor equal to zero gives the solutions y=16y = 16y=16 and y=−52y = -\frac{5}{2}y=−25 .
Learning Objectives
- Apply the quadratic formula to determine the solutions of quadratic equations.