Solve the equation below by factoring. t ( 3 t + 19 ) = 40 t ( 3 t + 19 ) = 40 t ( 3 t + 19 ) = 40 A) t = 5 3 t = \frac { 5 } { 3 } t = 3 5 and t = − 8 t = - 8 t = − 8 B) t = − 5 3 t = - \frac { 5 } { 3 } t = − 3 5 and t = 8 t = 8 t = 8 C) t = 5 3 t = \frac { 5 } { 3 } t = 3 5 and t = 8 t = 8 t = 8 D) t = − 5 3 t = - \frac { 5 } { 3 } t = − 3 5 and t = − 8 t = - 8 t = − 8 E) t = 0 and t = 19 t = 0 ext { and } t = 19 t = 0 and t = 19

Question

Solve the equation below by factoring.   t ( 3 t + 19 )  = 40 t ( 3 t + 19 )  = 40 t ( 3 t + 19 )  = 40 A)    t = 5 3 t = \frac { 5 } { 3 } t = 3 5 ​   and   t = − 8 t = - 8 t = − 8 B)    t = − 5 3 t = - \frac { 5 } { 3 } t = − 3 5 ​   and   t = 8 t = 8 t = 8 C)    t = 5 3 t = \frac { 5 } { 3 } t = 3 5 ​   and   t = 8 t = 8 t = 8 D)    t = − 5 3 t = - \frac { 5 } { 3 } t = − 3 5 ​   and   t = − 8 t = - 8 t = − 8 E)    t = 0  and  t = 19 t = 0 	ext { and } t = 19 t = 0  and  t = 19

Shreyan Patel · Accepted Answer

Final Answer : A, Explanation :   First, expand and rearrange the equation to standard form:   3 t 2 + 19 t − 40 = 0 3t^2 + 19t - 40 = 0 3 t 2 + 19 t − 40 = 0  . Factoring this quadratic equation, we find the solutions   t = 5 3 t = \frac{5}{3} t = 3 5 ​   and   t = − 8 t = -8 t = − 8  .

Solve the equation below by factoring. $t (3 t + 19) = 40$

A) $\frac { 5 } { 3 }$ and $t = - 8$
B) $\frac { 5 } { 3 }$ and $t = 8$
C) $\frac { 5 } { 3 }$ and $t = 8$
D) $\frac { 5 } { 3 }$ and $t = - 8$
E) $\text { and } t = 19$

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