Asked by giggly puffs on May 07, 2024
Verified
Solve the equation below by factoring. x2−49=0x ^ { 2 } - 49 = 0x2−49=0
A) x=−7x = - 7x=−7 and x=7x = 7x=7
B) x=7x = 7x=7
C) x=−7x = - 7x=−7
D) x=0x = 0x=0 and x=7x = 7x=7
E) x=−7x = - 7x=−7 and x=0x = 0x=0
Equation
A mathematical statement expressing the equality of two expressions, typically involving variables and constants.
Factoring
The process of breaking down an equation or expression into simpler components that, when multiplied together, return the original equation or expression.
- Factor expressions using common factoring techniques, including grouping and square of a binomial.
Verified Answer
HM
Hallie MoffittMay 09, 2024
Final Answer :
A
Explanation :
We can factor the equation as:
x2−49=0⇒(x−7)(x+7)=0x ^ { 2 } - 49 = 0 \Rightarrow (x-7)(x+7)=0x2−49=0⇒(x−7)(x+7)=0
Using the zero product property, we get:
x−7=0 or x+7=0x-7=0 \text{ or } x+7=0x−7=0 or x+7=0
which gives us:
x=7 or x=−7x=7 \text{ or } x=-7x=7 or x=−7
Thus, the answer is choice A.
x2−49=0⇒(x−7)(x+7)=0x ^ { 2 } - 49 = 0 \Rightarrow (x-7)(x+7)=0x2−49=0⇒(x−7)(x+7)=0
Using the zero product property, we get:
x−7=0 or x+7=0x-7=0 \text{ or } x+7=0x−7=0 or x+7=0
which gives us:
x=7 or x=−7x=7 \text{ or } x=-7x=7 or x=−7
Thus, the answer is choice A.
Learning Objectives
- Factor expressions using common factoring techniques, including grouping and square of a binomial.