Solve the system by the method of substitution. { x − y 2 = 0 x − y = 42 \left\{ \begin{array} { l } x - y ^ { 2 } = 0 \x - y = 42\end{array} ight. { x − y 2 = 0 x − y = 42 A) ( 36 , 6 ) , ( 25 , − 5 ) ( 36,6 ) , ( 25 , - 5 ) ( 36 , 6 ) , ( 25 , − 5 ) B) ( 36 , − 6 ) , ( 25 , 5 ) ( 36 , - 6 ) , ( 25,5 ) ( 36 , − 6 ) , ( 25 , 5 ) C) ( 36 , 6 ) , ( 49 , − 7 ) ( 36,6 ) , ( 49 , - 7 ) ( 36 , 6 ) , ( 49 , − 7 ) D) ( 36 , − 6 ) , ( 49 , 7 ) ( 36 , - 6 ) , ( 49,7 ) ( 36 , − 6 ) , ( 49 , 7 ) E) no solution exists

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Solve the system by the method of substitution.   { x − y 2 = 0 x − y = 42 \left\{ \begin{array} { l } x - y ^ { 2 } = 0 \x - y = 42\end{array} ight. { x − y 2 = 0 x − y = 42 ​ A)    ( 36 , 6 )  , ( 25 , − 5 )  ( 36,6 )  , ( 25 , - 5 )  ( 36 , 6 )  , ( 25 , − 5 )  B)    ( 36 , − 6 )  , ( 25 , 5 )  ( 36 , - 6 )  , ( 25,5 )  ( 36 , − 6 )  , ( 25 , 5 )  C)    ( 36 , 6 )  , ( 49 , − 7 )  ( 36,6 )  , ( 49 , - 7 )  ( 36 , 6 )  , ( 49 , − 7 )  D)    ( 36 , − 6 )  , ( 49 , 7 )  ( 36 , - 6 )  , ( 49,7 )  ( 36 , − 6 )  , ( 49 , 7 )  E) no solution exists

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Solve the system by the method of substitution. ${x−y2=0x−y=42\left\{ \begin{array} { l } x - y ^ { 2 } = 0 \\x - y = 42\end{array} \right.$

A) $(36, 6), (25, - 5)$
B) $(36, - 6), (25, 5)$
C) $(36, 6), (49, - 7)$
D) $(36, - 6), (49, 7)$
E) no solution exists

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