Asked by Ethan Belka on Apr 25, 2024
Verified
Solve the system of linear equations below by the method of elimination. {9x+4y=−108−7x+2y=38\left\{ \begin{array} { l } 9 x + 4 y = - 108 \\- 7 x + 2 y = 38\end{array} \right.{9x+4y=−108−7x+2y=38
A) (1,7)
B) (-8,-9)
C) (1,0)
D) (-2,2)
E) (1,-7)
Linear Equations
Equations between two variables that produce a straight line when graphed on a Cartesian coordinate system.
Method Of Elimination
A technique for solving systems of equations by adding or subtracting the equations to eliminate one of the variables.
- Apply the method of elimination and substitution in solving systems of equations.
Verified Answer
KS
Klyzer Seijuro4 days ago
Final Answer :
B
Explanation :
To solve the system of equations by elimination, we aim to eliminate one variable by adding or subtracting the equations. First, we can multiply the second equation by 2 to make the coefficients of yyy in both equations equal:Original equations:1. 9x+4y=−1089x + 4y = -1089x+4y=−108 2. −7x+2y=38-7x + 2y = 38−7x+2y=38 Multiply the second equation by 2:1. 9x+4y=−1089x + 4y = -1089x+4y=−108 2. −14x+4y=76-14x + 4y = 76−14x+4y=76 Now, subtract the second equation from the first to eliminate yyy : 9x−(−14x)=−108−769x - (-14x) = -108 - 769x−(−14x)=−108−7623x=−18423x = -18423x=−184x=−184/23x = -184 / 23x=−184/23x=−8x = -8x=−8 Substitute x=−8x = -8x=−8 into one of the original equations to find yyy . Using the first equation: 9(−8)+4y=−1089(-8) + 4y = -1089(−8)+4y=−108−72+4y=−108-72 + 4y = -108−72+4y=−1084y=−108+724y = -108 + 724y=−108+724y=−364y = -364y=−36y=−9y = -9y=−9 Therefore, the solution to the system of equations is x=−8,y=−9x = -8, y = -9x=−8,y=−9 , which corresponds to choice B.
Learning Objectives
- Apply the method of elimination and substitution in solving systems of equations.
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