Asked by ARIELA FERMIN GARCIA on Apr 24, 2024
Verified
Three capacitors, a 12 μ F, a 20 μ F and a 30 μ F, are connected in series. What is the total capacitance?
A) 6 μ F
B) 62 μ F
Series Connection
An electrical circuit arrangement where components are connected end-to-end in a single path for current to flow.
Total Capacitance
In parallel circuits, it's the sum of individual capacitances of all capacitors, and in series circuits, it's calculated through the reciprocal of the sum of the reciprocals of the individual capacitances.
μ F
Microfarad, a unit of capacitance equal to one millionth (10^-6) of a farad, symbolized as µF.
- Compute the aggregate capacitance in capacitor circuits arranged in series and parallel configurations.
Verified Answer
CL
Chandra Lal Chhetri4 days ago
Final Answer :
A
Explanation :
The total capacitance, CtotalC_{total}Ctotal , of capacitors in series is given by the reciprocal of the sum of the reciprocals of the individual capacitances: 1Ctotal=1C1+1C2+1C3\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}Ctotal1=C11+C21+C31 . Substituting the given values, 1Ctotal=112+120+130\frac{1}{C_{total}} = \frac{1}{12} + \frac{1}{20} + \frac{1}{30}Ctotal1=121+201+301 , solving this gives Ctotal=6μFC_{total} = 6 \mu FCtotal=6μF .
Learning Objectives
- Compute the aggregate capacitance in capacitor circuits arranged in series and parallel configurations.