Asked by Hunter Smith on Mar 10, 2024

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Use log⁡366=0.5000\log _ { 36 } 6 = 0.5000log366=0.5000 , log⁡364≈0.3869\log _ { 36 } 4 \approx 0.3869log3640.3869 , and the properties of logarithms to approximate log⁡36144\log _ { 36 } 144log36144 to four decimal places. Do not use a calculator.

A) 4.96784.96784.9678
B) 4.59674.59674.5967
C) 4.45064.45064.4506
D) 3.44343.44343.4434
E) 1.38691.38691.3869

Logarithm

The power to which a base, often 10 or e, needs to be elevated in order to generate a specific number.

Properties of Logarithms

Rules that simplify the manipulation and solving of logarithmic equations, such as product, quotient, and power rules.

  • Appraise primary and universal logarithms, including the employment of logarithmic traits.
  • Implement the rules of logarithms to streamline or determine the value of expressions.
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JM
Josue MedinaMar 10, 2024
Final Answer :
E
Explanation :
log⁡36144\log_{36}144log36144 can be simplified using the property of logarithms that log⁡b(an)=n⋅log⁡b(a)\log_b(a^n) = n \cdot \log_b(a)logb(an)=nlogb(a) . Since 144=362144 = 36^2144=362 , log⁡36144=log⁡36(362)=2⋅log⁡3636=2⋅1=2\log_{36}144 = \log_{36}(36^2) = 2\cdot\log_{36}36 = 2\cdot1 = 2log36144=log36(362)=2log3636=21=2 . However, none of the options match this directly. The given values can be used to approximate log⁡36144\log_{36}144log36144 by expressing 144 as a product of 6 and 4, both of whose logarithms are given. Specifically, 144=62⋅4144 = 6^2 \cdot 4144=624 , so log⁡36144=log⁡36(62)+log⁡36(4)=2⋅log⁡36(6)+log⁡36(4)=2⋅0.5000+0.3869=1.3869\log_{36}144 = \log_{36}(6^2) + \log_{36}(4) = 2\cdot\log_{36}(6) + \log_{36}(4) = 2\cdot0.5000 + 0.3869 = 1.3869log36144=log36(62)+log36(4)=2log36(6)+log36(4)=20.5000+0.3869=1.3869 .