Asked by gaurang narang on May 21, 2024
Verified
Use synthetic division to divide. 2x5−3x3+x+15x−3\frac { 2 x ^ { 5 } - 3 x ^ { 3 } + x + 15 } { x - 3 }x−32x5−3x3+x+15
A) 2x4+4x3+39x2+97x+213+399x−32 x ^ { 4 } + 4 x ^ { 3 } + 39 x ^ { 2 } + 97 x + 213 + \frac { 399 } { x - 3 }2x4+4x3+39x2+97x+213+x−3399
B) 2x4−6x3+15x2−45x+136−393x−32 x ^ { 4 } - 6 x ^ { 3 } + 15 x ^ { 2 } - 45 x + 136 - \frac { 393 } { x - 3 }2x4−6x3+15x2−45x+136−x−3393
C) 2x4+5x3+25x2+54x+129+156x−32 x ^ { 4 } + 5 x ^ { 3 } + 25 x ^ { 2 } + 54 x + 129 + \frac { 156 } { x - 3 }2x4+5x3+25x2+54x+129+x−3156
D) 2x4+6x3+15x2+45x+136+423x−32 x ^ { 4 } + 6 x ^ { 3 } + 15 x ^ { 2 } + 45 x + 136 + \frac { 423 } { x - 3 }2x4+6x3+15x2+45x+136+x−3423
E) 2x4+3x3+7x2+69x+161+218x−32 x ^ { 4 } + 3 x ^ { 3 } + 7 x ^ { 2 } + 69 x + 161 + \frac { 218 } { x - 3 }2x4+3x3+7x2+69x+161+x−3218
Synthetic Division
A simplified manual method for dividing polynomials, particularly useful for dividing by linear factors.
- Understand and apply the concept of synthetic division.
Verified Answer
DM
Divishtha MalikMay 27, 2024
Final Answer :
D
Explanation :
The synthetic division process is shown below:
\begin{array}{rrrrrr|r}
3 & 2 & 0 & -3 & 1 & 15 & \\
& & 6 & 18 & 45 & 138 & \\\cline{2-7}
& 2 & 6 & 15 & 46 & 153 & \color{red}\boxed{+ \frac{423}{x-3}} \\
\end{array}
Thus, the quotient is $2x^4+6x^3+15x^2+45x+136$ with a remainder of $\frac{423}{x-3}$. The correct answer choice is (D).
\begin{array}{rrrrrr|r}
3 & 2 & 0 & -3 & 1 & 15 & \\
& & 6 & 18 & 45 & 138 & \\\cline{2-7}
& 2 & 6 & 15 & 46 & 153 & \color{red}\boxed{+ \frac{423}{x-3}} \\
\end{array}
Thus, the quotient is $2x^4+6x^3+15x^2+45x+136$ with a remainder of $\frac{423}{x-3}$. The correct answer choice is (D).
Learning Objectives
- Understand and apply the concept of synthetic division.