Asked by Yamaris Estrella on Apr 27, 2024
Verified
Use the properties of logarithms to condense 4ln3−3lnx−lny4 \ln 3 - 3 \ln x - \ln y4ln3−3lnx−lny .
A) ln(81−x3−y) \ln \left( 81 - x ^ { 3 } - y \right) ln(81−x3−y)
B) ln12x3y\ln \frac { 12 x ^ { 3 } } { y }lny12x3
C) ln81x3y\ln \frac { 81 x ^ { 3 } } { y }lny81x3
D) ln(12−3x−y) \ln ( 12 - 3 x - y ) ln(12−3x−y)
E) ln81x3y\ln \frac { 81 } { x ^ { 3 } y }lnx3y81
Logarithms
The exponent or power to which a base must be raised to produce a given number, typically used in solving exponential equations.
Condense
In mathematics, to simplify an expression or equation by combining like terms or using algebraic methods to make it more compact.
- Apply the properties of logarithms to expand and condense expressions.
Verified Answer
WP
Wilawan PalachumApr 28, 2024
Final Answer :
E
Explanation :
Using the properties of logarithms, 4ln3−3lnx−lny4 \ln 3 - 3 \ln x - \ln y4ln3−3lnx−lny can be condensed as follows: - 4ln34 \ln 34ln3 becomes ln34\ln 3^4ln34 or ln81\ln 81ln81 ,- −3lnx-3 \ln x−3lnx becomes −lnx3-\ln x^3−lnx3 or ln1x3\ln \frac{1}{x^3}lnx31 ,- −lny- \ln y−lny becomes ln1y\ln \frac{1}{y}lny1 .Combining these using the property that lna+lnb=ln(ab)\ln a + \ln b = \ln (ab)lna+lnb=ln(ab) and lna−lnb=ln(ab)\ln a - \ln b = \ln \left(\frac{a}{b}\right)lna−lnb=ln(ba) , we get ln81x3y\ln \frac{81}{x^3 y}lnx3y81 .
Learning Objectives
- Apply the properties of logarithms to expand and condense expressions.
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