Asked by Simon Sazian on May 21, 2024

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Verified

Use the properties of logarithms to condense 6log⁡10(x+y) +4log⁡10w6 \log _ { 10 } ( x + y ) + 4 \log _ { 10 } w6log10(x+y) +4log10w .

A) log⁡10x6y6w4\log _ { 10 } x ^ { 6 } y ^ { 6 } w ^ { 4 }log10x6y6w4
B) log⁡10(x6+y6) w4\log _ { 10 } \left( x ^ { 6 } + y ^ { 6 } \right) w ^ { 4 }log10(x6+y6) w4
C) log⁡10(6(x+y) +4w) \log _ { 10 } ( 6 ( x + y ) + 4 w ) log10(6(x+y) +4w)
D) log⁡1024(x+y) w\log _ { 10 } 24 ( x + y ) wlog1024(x+y) w
E) log⁡10(x+y) 6w4\log _ { 10 } ( x + y ) ^ { 6 } w ^ { 4 }log10(x+y) 6w4

Properties

Characteristics or attributes that help define mathematical operations or objects.

Logarithms

The power to which a base, usually 10 or e, needs to be elevated to result in a specific number.

Condense

To condense means to make something denser or more concentrated by reducing its volume or content without losing essential elements.

  • Activate logarithmic properties to perform both expansion and condensation of logarithms.
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Verified Answer

JH
Jacob HusikMay 25, 2024
Final Answer :
E
Explanation :
Using the property that states that the sum of logarithms is equivalent to the logarithm of the product, we can rewrite the expression as:

6log⁡10(x+y)+4log⁡10w=log⁡10(x+y)6+log⁡10w46 \log_{10}(x+y) + 4 \log_{10}w = \log_{10}(x+y)^6 + \log_{10}w^4 6log10(x+y)+4log10w=log10(x+y)6+log10w4

Then, using the property that states that the logarithm of a product is equivalent to the sum of logarithms, we can condense the expression as:

log⁡10(x+y)6+log⁡10w4=log⁡10(x+y)6w4\log_{10}(x+y)^6 + \log_{10}w^4 = \log_{10}(x+y)^6w^4log10(x+y)6+log10w4=log10(x+y)6w4

This matches answer choice E, so the best choice is E.