Asked by Simon Sazian on May 21, 2024
Verified
Use the properties of logarithms to condense 6log10(x+y) +4log10w6 \log _ { 10 } ( x + y ) + 4 \log _ { 10 } w6log10(x+y) +4log10w .
A) log10x6y6w4\log _ { 10 } x ^ { 6 } y ^ { 6 } w ^ { 4 }log10x6y6w4
B) log10(x6+y6) w4\log _ { 10 } \left( x ^ { 6 } + y ^ { 6 } \right) w ^ { 4 }log10(x6+y6) w4
C) log10(6(x+y) +4w) \log _ { 10 } ( 6 ( x + y ) + 4 w ) log10(6(x+y) +4w)
D) log1024(x+y) w\log _ { 10 } 24 ( x + y ) wlog1024(x+y) w
E) log10(x+y) 6w4\log _ { 10 } ( x + y ) ^ { 6 } w ^ { 4 }log10(x+y) 6w4
Properties
Characteristics or attributes that help define mathematical operations or objects.
Logarithms
The power to which a base, usually 10 or e, needs to be elevated to result in a specific number.
Condense
To condense means to make something denser or more concentrated by reducing its volume or content without losing essential elements.
- Activate logarithmic properties to perform both expansion and condensation of logarithms.
Verified Answer
JH
Jacob HusikMay 25, 2024
Final Answer :
E
Explanation :
Using the property that states that the sum of logarithms is equivalent to the logarithm of the product, we can rewrite the expression as:
6log10(x+y)+4log10w=log10(x+y)6+log10w46 \log_{10}(x+y) + 4 \log_{10}w = \log_{10}(x+y)^6 + \log_{10}w^4 6log10(x+y)+4log10w=log10(x+y)6+log10w4
Then, using the property that states that the logarithm of a product is equivalent to the sum of logarithms, we can condense the expression as:
log10(x+y)6+log10w4=log10(x+y)6w4\log_{10}(x+y)^6 + \log_{10}w^4 = \log_{10}(x+y)^6w^4log10(x+y)6+log10w4=log10(x+y)6w4
This matches answer choice E, so the best choice is E.
6log10(x+y)+4log10w=log10(x+y)6+log10w46 \log_{10}(x+y) + 4 \log_{10}w = \log_{10}(x+y)^6 + \log_{10}w^4 6log10(x+y)+4log10w=log10(x+y)6+log10w4
Then, using the property that states that the logarithm of a product is equivalent to the sum of logarithms, we can condense the expression as:
log10(x+y)6+log10w4=log10(x+y)6w4\log_{10}(x+y)^6 + \log_{10}w^4 = \log_{10}(x+y)^6w^4log10(x+y)6+log10w4=log10(x+y)6w4
This matches answer choice E, so the best choice is E.
Learning Objectives
- Activate logarithmic properties to perform both expansion and condensation of logarithms.
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