Write the logarithmic equation log ⁡ 2 1 32 = − 5 \log _ { 2 } \frac { 1 } { 32 } = - 5 lo g 2 32 1 = − 5 in exponential form.A) 2 − 5 = 1 32 2 ^ { - 5 } = \frac { 1 } { 32 } 2 − 5 = 32 1 B) 2 − 5 = − 1 32 2 ^ { - 5 } = - \frac { 1 } { 32 } 2 − 5 = − 32 1 C) 5 2 = 1 10 5 ^ { 2 } = \frac { 1 } { 10 } 5 2 = 10 1 D) 5 2 = 32 5 ^ { 2 } = 32 5 2 = 32 E) 2 − 5 = 1 5 2 ^ { - 5 } = \frac { 1 } { 5 } 2 − 5 = 5 1

Question

Write the logarithmic equation   log ⁡ 2 1 32 = − 5 \log _ { 2 } \frac { 1 } { 32 } = - 5 lo g 2 ​ 32 1 ​ = − 5   in exponential form.A)    2 − 5 = 1 32 2 ^ { - 5 } = \frac { 1 } { 32 } 2 − 5 = 32 1 ​ B)    2 − 5 = − 1 32 2 ^ { - 5 } = - \frac { 1 } { 32 } 2 − 5 = − 32 1 ​ C)    5 2 = 1 10 5 ^ { 2 } = \frac { 1 } { 10 } 5 2 = 10 1 ​ D)    5 2 = 32 5 ^ { 2 } = 32 5 2 = 32 E)    2 − 5 = 1 5 2 ^ { - 5 } = \frac { 1 } { 5 } 2 − 5 = 5 1 ​

AM - 09ZZ - AEC South (2392) · Accepted Answer

Final Answer : A, Explanation :  In logarithmic form, the base of the logarithm is raised to the power of the result and equals the argument. So, we have $2^{-5}=\frac{1}{32}$.

Write the logarithmic equation $log⁡2132=−5\log _ { 2 } \frac { 1 } { 32 } = - 5$ in exponential form.

A) $\frac { 1 } { 32 }$
B) $\frac { 1 } { 32 }$
C) $\frac { 1 } { 10 }$
D) $5 ^ { 2 } = 32$
E) $\frac { 1 } { 5 }$

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