Asked by Jackson Mathias on Sep 23, 2024
Verified
Write the standard form of the equation of the ellipse.
A) (x+2) 29+y216=1\frac { ( x + 2 ) ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 16 } = 19(x+2) 2+16y2=1
B) (x−2) 29+y216=1\frac { ( x - 2 ) ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 16 } = 19(x−2) 2+16y2=1
C) x2+29+y216=1\frac { x ^ { 2 } + 2 } { 9 } + \frac { y ^ { 2 } } { 16 } = 19x2+2+16y2=1
D) (x−2) 26+y28=1\frac { ( x - 2 ) ^ { 2 } } { 6 } + \frac { y ^ { 2 } } { 8 } = 16(x−2) 2+8y2=1
E) (x+2) 23+y24=1\frac { ( x + 2 ) ^ { 2 } } { 3 } + \frac { y ^ { 2 } } { 4 } = 13(x+2) 2+4y2=1
Equation
A statement that asserts the equality of two mathematical expressions, often containing one or more variables.
- Develop the ability to deduce and elucidate the standard configurations of ellipses' equations.
Verified Answer
SK
Sara Kate Rushingabout 15 hours ago
Final Answer :
B
Explanation :
Standard form of the equation of an ellipse with center (h,k), horizontal axis length 2a, and vertical axis length 2b is $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$. By comparing the given equation with the standard form, we get $\frac{(x-(-2))^2}{3^2}+\frac{y^2}{4^2}=1$ which simplifies to $\frac{(x+2)^2}{9}+\frac{y^2}{16}=1$. Thus, the correct choice is B.
Learning Objectives
- Develop the ability to deduce and elucidate the standard configurations of ellipses' equations.
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