Asked by Bijeta Pradhan on Jun 07, 2024

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Write the standard form of the equation of the ellipse centered at the origin, having a horizontal major axis of 6 units and a minor axis of 4 units.

A) x26+y24=1\frac { x ^ { 2 } } { 6 } + \frac { y ^ { 2 } } { 4 } = 16x2+4y2=1
B) x29+y24=1\frac { x ^ { 2 } } { 9 } + \frac { y ^ { 2 } } { 4 } = 19x2+4y2=1
C) x216+y236=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 36 } = 116x2+36y2=1
D) x28+y218=1\frac { x ^ { 2 } } { 8 } + \frac { y ^ { 2 } } { 18 } = 18x2+18y2=1
E) x24+y29=1\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 9 } = 14x2+9y2=1

Standard Form

A way to write numbers using the digits 0-9, where each digit has its place value; in linear equations, Ax + By = C, where A, B, and C are integers.

Ellipse

A curve on a plane that surrounds two focal points such that the sum of the distances to the two focal points is constant for every point on the curve.

Major Axis

The longest diameter of an ellipse, running through its center and both foci.

  • Gain insight into the standard equation formats for delineating ellipses and hyperbolas.
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Verified Answer

ZK
Zybrea KnightJun 07, 2024
Final Answer :
B
Explanation :
The standard form of the equation of an ellipse centered at the origin with a horizontal major axis is x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1a2x2+b2y2=1 , where 2a2a2a is the length of the major axis and 2b2b2b is the length of the minor axis. Given a major axis of 6 units and a minor axis of 4 units, a=3a = 3a=3 and b=2b = 2b=2 , so the equation becomes x29+y24=1\frac{x^2}{9} + \frac{y^2}{4} = 19x2+4y2=1 .