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LM

Lalit Maharaj

4 days ago

What term should be added to y2−15yy ^ { 2 } - \frac { 1 } { 5 } yy2−51​y to make it a perfect square trinomial?

A) 5
B) 1100\frac { 1 } { 100 }1001​
C) 100
D) 52 \frac{5}{2} 25​
E) 150\frac { 1 } { 50 }501​
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BG

Brevin Goodlett

4 days ago

Use ln⁡6≈1.7918\ln 6 \approx 1.7918ln6≈1.7918 , ln⁡10≈2.3026\ln 10 \approx 2.3026ln10≈2.3026 , and the properties of logarithms to approximate ln⁡60\ln \sqrt { 60 }ln60​ to four decimal places.

A) 2.06282.06282.0628
B) 16.763716.763716.7637
C) 2.04722.04722.0472
D) 8.18878.18878.1887
E) 2.72722.72722.7272
RF

Rhonda Fritzshall

4 days ago

Use the properties of logarithms to evaluate log⁡279+log⁡2781\log _ { 27 } 9 + \log _ { 27 } 81log27​9+log27​81 without a calculator.

A) 2
B) 23 \frac{2}{3} 32​
C) 34 \frac{3}{4} 43​
D) 4
E) 1
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MW

Madison Widdecombe

4 days ago

An investment of $500 is made in a trust fund at an annual interest rate of 5%, compounded monthly. How long will it take for the investment to double? Give your answer to two decimal places.

A) 13.8913.8913.89 years
B) 166.70166.70166.70 years
C) 1.061.061.06 years
D) 13.8613.8613.86 years
E) 20.0020.0020.00 years
PO

Patrick O'Leary

4 days ago

Use the properties of logarithms to expand xx−11\frac { \sqrt { x } } { x - 11 }x−11x​​ .

A) 12ln⁡x−ln⁡(x−11) \frac { 1 } { 2 } \ln x - \ln ( x - 11 ) 21​lnx−ln(x−11)
B) ln⁡(12x−x11) \ln \left( \frac { 1 } { 2 } x - \frac { x } { 11 } \right) ln(21​x−11x​)
C) (ln⁡x) 1/2ln⁡x−ln⁡11\frac { ( \ln x ) ^ { 1 / 2 } } { \ln x - \ln 11 }lnx−ln11(lnx) 1/2​
D) (ln⁡x) 1/2−ln⁡(x−11) ( \ln x ) ^ { 1 / 2 } - \ln ( x - 11 ) (lnx) 1/2−ln(x−11)
E) 12ln⁡x⋅(ln⁡x−ln⁡11) \frac { 1 } { 2 } \ln x \cdot ( \ln x - \ln 11 ) 21​lnx⋅(lnx−ln11)
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MK

Michael Kassim

4 days ago

Suppose the number of DVDs shipped by DVD manufacturers in a region in 1997 was 200,000. In 2000, the number had increased to 3,700,000 If it is assumed that number of DVDs shipped by manufactures grows at an exponential rate, how many DVDs will be shipped in 2010. Round your answer to the nearest hundred thousand.

A) 61,959,400,000
B) 433,399,700,000
C) 21,200,000
D) 23,427,000,000
E) 3,349,200,000
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AG

Arjun Ganguly

4 days ago

Write the logarithmic equation log⁡2132=−5\log _ { 2 } \frac { 1 } { 32 } = - 5log2​321​=−5 in exponential form.

A) 2−5=1322 ^ { - 5 } = \frac { 1 } { 32 }2−5=321​
B) 2−5=−1322 ^ { - 5 } = - \frac { 1 } { 32 }2−5=−321​
C) 52=1105 ^ { 2 } = \frac { 1 } { 10 }52=101​
D) 52=325 ^ { 2 } = 3252=32
E) 2−5=152 ^ { - 5 } = \frac { 1 } { 5 }2−5=51​
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AJ

Alisa Jackson

4 days ago

Find the intercepts of y=9x2−8x+8y = 9 x ^ { 2 } - 8 x + 8y=9x2−8x+8 .

A) x -intercept: (−49,0) \left( - \frac { 4 } { 9 } , 0 \right) (−94​,0) y -intercepts: (0,8)
B) no x -intercepts y -intercept: (0,8)
C) x -intercept: (8,0) no y -intercepts
D) no x -intercepts y -intercept: (0,-8)
E) x -intercept: (8,0) y -intercept: (0,8)
AE

Adriana Espinoza

4 days ago

Determine if x=-6 satisfies 0<x+56<20 < \frac { x + 5 } { 6 } < 20<6x+5​<2 .

A) x=-6 does satisfy the inequality.
B) x=-6 does not satisfy the inequality.
CC

Cryztal Celeste

4 days ago

A free-falling object is described by h=35t+12at2h = 35 t + \frac { 1 } { 2 } a t ^ { 2 }h=35t+21​at2 , where h is the height above the ground, t is the amount of time the object is falling, and a is the acceleration. Solve the equation for a .

A) a=2(h−35t) ta = \frac { 2 ( h - 35 t ) } { t }a=t2(h−35t) ​
B) a=2(h+35t) t2a = \frac { 2 ( h + 35 t ) } { t ^ { 2 } }a=t22(h+35t) ​
C) a=2(h−35t) t2a = \frac { 2 ( h - 35 t ) } { t ^ { 2 } }a=t22(h−35t) ​
D) a=h−35tt2a = \frac { h - 35 t } { t ^ { 2 } }a=t2h−35t​
E) a=h−35t2t2a = \frac { h - 35 t } { 2 t ^ { 2 } }a=2t2h−35t​
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KR

Kimberly Romanger

4 days ago

Completely factor the polynomial x3−57x+56x ^ { 3 } - 57 x + 56x3−57x+56 given one of its factors is x-7 .

A) (x−7) (x−1) (x+8) ( x - 7 ) ( x - 1 ) ( x + 8 ) (x−7) (x−1) (x+8)
B) (x−7) (x−2) (x+16) ( x - 7 ) ( x - 2 ) ( x + 16 ) (x−7) (x−2) (x+16)
C) (x−7) (x+2) (x+24) ( x - 7 ) ( x + 2 ) ( x + 24 ) (x−7) (x+2) (x+24)
D) (x−7) (x−3) (x+32) ( x - 7 ) ( x - 3 ) ( x + 32 ) (x−7) (x−3) (x+32)
E) (x−7) (x+1) (x−9) ( x - 7 ) ( x + 1 ) ( x - 9 ) (x−7) (x+1) (x−9)
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JP

Jessica Price

4 days ago

Rewrite the expression using only positive exponents, and simplify. Assume that any variables in the expression are nonzero. s−1+r−1s−1−r−1\frac { s ^ { - 1 } + r ^ { - 1 } } { s ^ { - 1 } - r ^ { - 1 } }s−1−r−1s−1+r−1​

A) r−sr+s\frac { r - s } { r + s }r+sr−s​
B) s2+r2s ^ { 2 } + r ^ { 2 }s2+r2
C) r+sr−s\frac { r + s } { r - s }r−sr+s​
D) s+rs−r\frac { s + r } { s - r }s−rs+r​
E) s−rs+r\frac { s - r } { s + r }s+rs−r​
ND

Narayan Dawadi

4 days ago

Write an absolute value inequality that represents the verbal statement, The set of all real numbers x whose distance from 0 is less than 888 .

A) ∣x∣<8| x | < 8∣x∣<8
B) ∣x−8∣>0| x - 8 | > 0∣x−8∣>0
C) ∣x∣>8| x | > 8∣x∣>8
D) ∣x∣≤8| x | \leq 8∣x∣≤8
E) ∣x−8∣≥0| x - 8 | \geq 0∣x−8∣≥0
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VK

Valeria Katona

4 days ago

Rewrite ∣y+6∣<5| y + 6 | < 5∣y+6∣<5 as a double inequality.

A) −5<y+6<5- 5 < y + 6 < 5−5<y+6<5
B) −6<y+6<5- 6 < y + 6 < 5−6<y+6<5
C) −6<y+6<6- 6 < y + 6 < 6−6<y+6<6
D) −5<y+6<11- 5 < y + 6 < 11−5<y+6<11
E) −6<y+5<5- 6 < y + 5 < 5−6<y+5<5
LC

Leandra Crowley

4 days ago

Two cars start at the same point and travel in the same direction at average speeds of 65 miles per hour and 40 miles per hour. How much time (in hours) must elapse before the two cars are 87.5 miles apart?

A) 3.5 hours
B) 3.49 hours
C) 1.35 hours
D) 0.830.830.83 hour
E) 2.192.192.19 hours
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SC

Scott Cregger

4 days ago

Use the rules of exponents to simplify the expression below. x4n+4y5n−5x3n+2yn−2\frac { x ^ { 4 n + 4 } y ^ { 5 n - 5 } } { x ^ { 3 n + 2 } y ^ { n - 2 } }x3n+2yn−2x4n+4y5n−5​

A) xn+2y4n−7x ^ { n + 2 } y ^ { 4 n - 7 }xn+2y4n−7
B) xn+6y4n−3x ^ { n + 6 } y ^ { 4 n - 3 }xn+6y4n−3
C) x7n+2y4x−3x ^ { 7 n + 2 } y ^ { 4 x - 3 }x7n+2y4x−3
D) xn+2y4n−3x ^ { n + 2 } y ^ { 4 n - 3 }xn+2y4n−3
E) x7n+2y4n−7x ^ { 7n+ 2 } y ^ { 4 n - 7 }x7n+2y4n−7
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HL

Harmony Lozoya

4 days ago

Find the x- and y- intercepts, if any, of y=18−25xy = 18 - \frac { 2 } { 5 } xy=18−52​x .

A) x- intercept at -45 , y- intercept at 18
B) x- intercept at 18 , y- intercept at 45
C) x- intercept at 45 , y- intercept at 18
D) x- intercept at -18, y- intercept at 45
E) no intercepts
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TM

terry michel

4 days ago

Use cross-multiplication to solve the equation x−34=1924\frac { x - 3 } { 4 } = \frac { 19 } { 24 }4x−3​=2419​ for x .

A) x= - 136\frac { 13 } { 6 }613​
B) x= 376\frac { 37 } { 6 }637​
C) x= - 16\frac { 1 } { 6 }61​
D) x= 136\frac { 13 } { 6 }613​
E) x= 16\frac { 1 } { 6 }61​
CM

Chris M Cole Jr.

4 days ago

Complete the table showing the equivalent forms of a percent. Reduce fractions to simplest form. Percent Parts out of 100 Decimal Fraction 65%

A)  Percent  Parts out of 100 Decimal  Fraction 65%650.651320\begin{array} { | c | c | c | c | } \hline \text { Percent } & \text { Parts out of } 100 & \text { Decimal } & \text { Fraction } \\\hline 65 \% & 65 & 0.65 & \frac { 13 } { 20 } \\\hline\end{array} Percent 65%​ Parts out of 10065​ Decimal 0.65​ Fraction 2013​​​
B)  Percent  Parts out of 100 Decimal  Fraction 65%0.651.5465100\begin{array} { | c | c | c | c | } \hline \text { Percent } & \text { Parts out of } 100 & \text { Decimal } & \text { Fraction } \\\hline 65 \% & 0.65 & 1.54 & \frac { 65 } { 100 } \\\hline\end{array} Percent 65%​ Parts out of 1000.65​ Decimal 1.54​ Fraction 10065​​​
C)  Percent  Parts aut of 100 Decimal  Fraction 65%650.02165\begin{array} { | c | c | c | c | } \hline \text { Percent } & \text { Parts aut of } 100 & \text { Decimal } & \text { Fraction } \\\hline 65 \% & 65 & 0.02 & \frac { 1 } { 65 } \\\hline\end{array} Percent 65%​ Parts aut of 10065​ Decimal 0.02​ Fraction 651​​​
D)  Percent  Parts out of 100 Decimal  Fraction 65%650.021320\begin{array} { | c | c | c | c | } \hline \text { Percent } & \text { Parts out of } 100 & \text { Decimal } & \text { Fraction } \\\hline 65 \% & 65 & 0.02 & \frac { 13 } { 20 } \\\hline\end{array} Percent 65%​ Parts out of 10065​ Decimal 0.02​ Fraction 2013​​​
E)  Percent  Parts out of 100 Decimal  Fraction 65%1.540.6565100\begin{array} { | c | c | c | c | } \hline \text { Percent } & \text { Parts out of } 100 & \text { Decimal } & \text { Fraction } \\\hline 65 \% & 1.54 & 0.65 & \frac { 65 } { 100 } \\\hline\end{array} Percent 65%​ Parts out of 1001.54​ Decimal 0.65​ Fraction 10065​​​
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HR

Hans Raj Joshi

4 days ago

If a product has a cost of $42.67 and a selling price of $63.33 , what is the markup rate? Round your answer to two decimal places.

A) 14.84%
B) 48.42%
C) 32.62%
D) 20.65%
E) 30.65%