Answers

BN

Answered

The number of kanbans decreases as safety stock is increased.

On Aug 01, 2024


False
BN

Answered

A restrictive short-term financial policy, as compared to a more flexible policy, tends to cause a firm to lose sales due to a lack of inventory on hand.

On Jul 30, 2024


True
BN

Answered

Which of these statements is generally accepted by economists? Perfect competition

A) provides both equity and efficiency.
B) provides equity but not necessarily efficiency.
C) provides efficiency but not necessarily equity.
D) generally satisfies neither efficiency nor equity.

On Jul 01, 2024


C
BN

Answered

(Last Word) Based on the concept of price elasticity of demand,which of the following cases is most likely to occur?

A) Golf courses charging higher prices for golf during the week than on weekends.
B) Movie theaters charging higher prices for senior citizens.
C) Colleges charging lower tuition for low-income students.
D) Airlines charging lower fares for business travelers.

On Jun 30, 2024


C
BN

Answered

The direct method of allocating support department costs to production using the ABC method is the easiest and most accurate.

On Jun 01, 2024


False
BN

Answered

Centralized communication networks work better on simple tasks.

On May 31, 2024


True
BN

Answered

Title VII covers all of the following issues EXCEPT:

A) recruiting.
B) promotion.
C) job training.
D) union membership.
E) wages.

On May 02, 2024


D
BN

Answered

Men and women engage in networking equally, except for ________.

On May 01, 2024


socializing
BN

Answered

The terms of trade will favor a larger nation over a smaller nation.

On Apr 30, 2024


False
BN

Answered

The defect rate for a product has historically been about 1.6%. What are the upper and lower control chart limits for a p-chart, if you wish to use a sample size of 100 and 3-sigma limits?

On Apr 28, 2024


UCLp =

pˉ\bar ppˉ + 3 pˉ(1−pˉ)n\sqrt { \frac{\bar p(1-\bar p)}{n}}npˉ(1pˉ) = 0.016 + 3 ∙ (0.016∗0.984)/100\sqrt { ( 0.016 * 0.984 ) / 100 }(0.0160.984)/100 = .0536
UCLp =

pˉ\bar ppˉ - 3 pˉ(1−pˉ)n\sqrt { \frac{\bar p(1-\bar p)}{n}}npˉ(1pˉ) = 0.016 - 3 ∙ (0.016∗0.984)/100\sqrt { ( 0.016 * 0.984 ) / 100 }(0.0160.984)/100 = 0.0216, or zero