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A free-falling object is described by h=35t+12at2h = 35 t + \frac { 1 } { 2 } a t ^ { 2 }h=35t+21at2 , where h is the height above the ground, t is the amount of time the object is falling, and a is the acceleration. Solve the equation for a .

A) a=2(h−35t) ta = \frac { 2 ( h - 35 t ) } { t }a=t2(h35t)
B) a=2(h+35t) t2a = \frac { 2 ( h + 35 t ) } { t ^ { 2 } }a=t22(h+35t)
C) a=2(h−35t) t2a = \frac { 2 ( h - 35 t ) } { t ^ { 2 } }a=t22(h35t)
D) a=h−35tt2a = \frac { h - 35 t } { t ^ { 2 } }a=t2h35t
E) a=h−35t2t2a = \frac { h - 35 t } { 2 t ^ { 2 } }a=2t2h35t

On Sep 27, 2024


C
QE

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Imperial Life Inc. is quoting a rate of return of 5.2% compounded quarterly on 15-year annuities. How much will you have to pay for a 15-year annuity that pays $5,000 (at the end of) every three months?

On Sep 22, 2024


$207,416.93