Asked by Jessica Strohmenger on May 20, 2024

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Find all real and complex solutions of the quadratic equation 6x2−5x=06 x ^ { 2 } - 5 x = 06x25x=0 .

A) 0,560,\frac { 5 } { 6 }0,65
B) 0,56i0 , \frac { 5 } { 6 } i0,65i
C) 365\frac { 36 } { 5 }536
D) 56i\frac { 5 } { 6 } i65i
E) 0,650 , \frac { 6 } { 5 }0,56

Complex Solutions

Solutions to equations that include the square root of a negative number, typically represented as a combination of a real number and an imaginary number.

Quadratic Equation

A polynomial equation of the second degree, typically presented in the form ax^2 + bx + c = 0, where a, b, and c are constants.

  • Tackle quadratic equations by utilizing the strategy of factorization.
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RB
Roshona BlanksMay 25, 2024
Final Answer :
A
Explanation :
Factoring out xxx gives x(6x−5)=0x(6x - 5) = 0x(6x5)=0 , leading to solutions x=0x = 0x=0 and x=56x = \frac{5}{6}x=65 .