Solve t 2 + 7 t = 0 t ^ { 2 } + 7 t = 0 t 2 + 7 t = 0 by factoring.A) t = 0 , t = 7 t = 0 , t = 7 t = 0 , t = 7 B) t=0C) t = 0 , t = − 7 t = 0 , t = - 7 t = 0 , t = − 7 D) t = 0 , t = 7 2 t = 0 , t = \frac { 7 } { 2 } t = 0 , t = 2 7 E) t=-7

Question

Solve   t 2 + 7 t = 0 t ^ { 2 } + 7 t = 0 t 2 + 7 t = 0   by factoring.A)    t = 0 , t = 7 t = 0 , t = 7 t = 0 , t = 7 B)  t=0C)    t = 0 , t = − 7 t = 0 , t = - 7 t = 0 , t = − 7 D)    t = 0 , t = 7 2 t = 0 , t = \frac { 7 } { 2 } t = 0 , t = 2 7 ​ E)  t=-7

Tiffany Green · Accepted Answer

Final Answer : C, Explanation :   The equation   t 2 + 7 t = 0 t^2 + 7t = 0 t 2 + 7 t = 0   can be factored as   t ( t + 7 ) = 0 t(t + 7) = 0 t ( t + 7 ) = 0  , which gives the solutions   t = 0 t = 0 t = 0   and   t = − 7 t = -7 t = − 7  .

Solve $t ^ { 2 } + 7 t = 0$ by factoring.

A) $t = 0, t = 7$
B) t=0
C) $t = 0, t = - 7$
D) $\frac { 7 } { 2 }$
E) t=-7

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Solve t2+7t=0t ^ { 2 } + 7 t = 0t2+7t=0 by factoring.A) t=0,t=7t = 0 , t = 7t=0,t=7 B) t=0C) t=0,t=−7t = 0 , t = - 7t=0,t=−7 D) t=0,t=72t = 0 , t = \frac { 7 } { 2 }t=0,t=27​ E) t=-7

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Learning Objectives

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Solve $t ^ { 2 } + 7 t = 0$ by factoring.

A) $t = 0, t = 7$
B) t=0
C) $t = 0, t = - 7$
D) $\frac { 7 } { 2 }$
E) t=-7