Asked by Tanesha Williams on May 25, 2024

verifed

Verified

Find all real and complex solutions of the quadratic equation (x+7) 2+28=0( x + 7 ) ^ { 2 } + 28 = 0(x+7) 2+28=0 .

A) 4±774 \pm 7 \sqrt { 7 }4±77
B) 7±277 \pm 2 \sqrt { 7 }7±27
C) 7±47i7 \pm 4 \sqrt { 7 } i7±47i
D) −2±77i- 2 \pm 7 \sqrt { 7 } i2±77i
E) −7±27i- 7 \pm 2 \sqrt { 7 } i7±27i

Complex Solutions

Solutions to an equation that include imaginary numbers, indicating they cannot be plotted on the standard real number line.

Real Solutions

Solutions to an equation that do not involve imaginary or complex numbers, and can be plotted on a real number line.

Quadratic Equation

A quadratic equation is a second-degree polynomial equation, typically in the form ax^2 + bx + c = 0, where a, b, and c are constants and a ≠ 0.

  • Ascertain both real and complex outcomes when solving quadratic equations.
verifed

Verified Answer

RK
Rubab KhalidMay 27, 2024
Final Answer :
E
Explanation :
First, simplify the given equation: (x+7)2+28=0(x + 7)^2 + 28 = 0(x+7)2+28=0 . Subtract 28 from both sides to get (x+7)2=−28(x + 7)^2 = -28(x+7)2=28 . Taking the square root of both sides gives x+7=±−28x + 7 = \pm \sqrt{-28}x+7=±28 . Simplifying the square root of -28 as 27i2\sqrt{7}i27i , we get x=−7±27ix = -7 \pm 2\sqrt{7}ix=7±27i .