Asked by bianca whiteley on May 15, 2024

verifed

Verified

Find all real and complex solutions of the quadratic equation x2+256=0x ^ { 2 } + 256 = 0x2+256=0 .

A) -256
B) ±256i\pm 256 i±256i
C) ±16\pm 16±16
D) ±16i\pm 16 i±16i
E) 16i16 i16i

Complex Solutions

Solutions to equations that include imaginary numbers, typically used when solving polynomial equations that do not have real-number solutions.

Real Solutions

The solutions of an equation that are real numbers, as opposed to imaginary or complex numbers.

Quadratic Equation

A mathematical equation where the highest power of an unknown variable is square.

  • Uncover both real and complex values as solutions to quadratic equations.
verifed

Verified Answer

MS
Megan StrettonMay 22, 2024
Final Answer :
D
Explanation :
To solve the quadratic equation x2+256=0x^2 + 256 = 0x2+256=0 , we can rearrange it to x2=−256x^2 = -256x2=256 . Taking the square root of both sides gives x=±−256x = \pm \sqrt{-256}x=±256 . Since the square root of a negative number involves the imaginary unit iii , where i2=−1i^2 = -1i2=1 , we get x=±256ix = \pm \sqrt{256}ix=±256i , which simplifies to x=±16ix = \pm 16ix=±16i .