If X and Y are random variables,the sum of all the conditional probabilities of X given a specific value of Y will always be:

A) 0.0
B) 1.0
C) the average of the possible values of X.
D) the average of the possible values of Y.

Solve accurate to the cent:
$\frac{x}{1.1^2}+2x(1.1{)}^3=\$1000$