Solve u ( u − 10 ) − 6 ( u − 10 ) = 0 u ( u - 10 ) - 6 ( u - 10 ) = 0 u ( u − 10 ) − 6 ( u − 10 ) = 0 by factoring.A) u = 6 , u = 10 u = 6 , u = 10 u = 6 , u = 10 B) u = 0 , u = 3 5 u = 0 , u = \frac { 3 } { 5 } u = 0 , u = 5 3 C) u = − 6 , u = − 10 u = - 6 , u = - 10 u = − 6 , u = − 10 D) u = 0 , u = 10 u = 0 , u = 10 u = 0 , u = 10 E) u = 6 , u = − 10 u = 6 , u = - 10 u = 6 , u = − 10

Question

Solve   u ( u − 10 )  − 6 ( u − 10 )  = 0 u ( u - 10 )  - 6 ( u - 10 )  = 0 u ( u − 10 )  − 6 ( u − 10 )  = 0   by factoring.A)    u = 6 , u = 10 u = 6 , u = 10 u = 6 , u = 10 B)    u = 0 , u = 3 5 u = 0 , u = \frac { 3 } { 5 } u = 0 , u = 5 3 ​ C)    u = − 6 , u = − 10 u = - 6 , u = - 10 u = − 6 , u = − 10 D)    u = 0 , u = 10 u = 0 , u = 10 u = 0 , u = 10 E)    u = 6 , u = − 10 u = 6 , u = - 10 u = 6 , u = − 10

Emily Henrie · Accepted Answer

Final Answer : A, Explanation :   Factoring out the common term   ( u − 10 ) (u - 10) ( u − 10 )  , we get   ( u − 10 ) ( u − 6 ) = 0 (u - 10)(u - 6) = 0 ( u − 10 ) ( u − 6 ) = 0  , which gives the solutions   u = 10 u = 10 u = 10   and   u = 6 u = 6 u = 6  .

Solve $u (u - 10) - 6 (u - 10) = 0$ by factoring.

A) $u = 6, u = 10$
B) $\frac { 3 } { 5 }$
C) $u = - 6, u = - 10$
D) $u = 0, u = 10$
E) $u = 6, u = - 10$

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