{Cars Narrative} Suppose you choose two families at random.What is the chance that they each own one car? (That means family A owns a car and family B owns a car.)

A) 0.23
B) 0.23 + 0.23 = 0.46
C) 0.23 + 0.23 − (0.23) *(0.23) = .4071
D) (0.23) *(0.23) = 0.0529

Multiply and simplify. $\frac{(x-4y{)}^2}{x+4y}\cdot \frac{x^2+10xy+24y^2}{x^2-16y^2}$

A) $\frac{(x+4y)(x-6y)}{x-4y},x\ne \pm 4y$
B) $x-4y,x\ne -6y$
C) $x+6y,x\ne 0$
D) $\frac{(x-4y)(x+6y)}{x+4y},x\ne \pm 4y$
E) $\frac{(x-6y)(x+6y)}{x+4y},x\ne 6y$